d-jet a.a.r. question, 8/18/ AAR open vs closed - effect on setting timing-advance |
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d-jet a.a.r. question, 8/18/ AAR open vs closed - effect on setting timing-advance |
DRPHIL914 |
Aug 10 2011, 08:50 PM
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#1
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Dr. Phil Group: Members Posts: 5,808 Joined: 9-December 09 From: Bluffton, SC Member No.: 11,106 Region Association: South East States |
I e tested 4 now and after 10 min none of them close completely or at all. Either way could it be because of a bad connection? Not hot enough? I know atleast one, the newest one was tested as good and is very clean. I know they can go bad inside but I do not think they all are.
But after 10 min of car at idle its still pulling air thru, suggestions please. Phil |
Tom |
Aug 11 2011, 08:33 AM
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#2
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Advanced Member Group: Members Posts: 2,139 Joined: 21-August 05 From: Port Orchard, WA 98367 Member No.: 4,626 Region Association: None |
The AAR typically draws about 1 to 1.5 amps. They measure in the neighborhood of 12-15 ohms. The battery and alternator determine voltage. If you have 12 ohms resistance in your AAR and 12 volts running voltage, then you have 1 amp of current. More resistance = less current. More voltage = more current. Since most properly operating charging systems have the car's voltage running at around 13.5 volts, the AAR usually draws a little more than 1 amp.
I ( current) = V(voltage)/ R ( resistance) or I= 13.5/12 or 1.125 amps Tom |
underthetire |
Aug 11 2011, 09:08 AM
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#3
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914 Guru Group: Members Posts: 5,062 Joined: 7-October 08 From: Brentwood Member No.: 9,623 Region Association: Northern California |
The AAR typically draws about 1 to 1.5 amps. They measure in the neighborhood of 12-15 ohms. The battery and alternator determine voltage. If you have 12 ohms resistance in your AAR and 12 volts running voltage, then you have 1 amp of current. More resistance = less current. More voltage = more current. Since most properly operating charging systems have the car's voltage running at around 13.5 volts, the AAR usually draws a little more than 1 amp. I ( current) = V(voltage)/ R ( resistance) or I= 13.5/12 or 1.125 amps Tom (IMG:style_emoticons/default/agree.gif) I bench tested one with a Tek power supply, at 13.5 volts it pulled ~1.2 cold, dropped slightly after heated. |
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