Self Sustaining Electric 914, jwalters is back |
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Self Sustaining Electric 914, jwalters is back |
1jwalters |
Nov 16 2013, 08:09 AM
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#101
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Newbie Group: Members Posts: 28 Joined: 15-November 13 From: Florida Member No.: 16,651 Region Association: None |
http://www.indiegogo.com/projects/self-sus...c-car/x/5342378
My latest project. Recently I designed a new generation wind turbine. I am going to miniaturize my design and work it into the front trunk area of a teener. My goal is to drive coast to coast non-stop........ Ambitious? Yes! Doable? Yes! I will accept any help thrown my way! (IMG:style_emoticons/default/drunk.gif) By the way, it is great to be back here, I missed this place! |
stugray |
Nov 20 2013, 11:54 AM
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#102
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Advanced Member Group: Members Posts: 3,825 Joined: 17-September 09 From: Longmont, CO Member No.: 10,819 Region Association: None |
Ok, lets put this in perspective using some physics.
If you had a air intake of one square meter (3.3 feet by 3.3 feet) If you had air moving through this intake at 25meter/second ( ~55 Miles per hour). Air weighs 1.205 kilograms/cubic-meter The total kinetic energy of of one cubic meter of air at 25 m/s is: E = 1/2*m*v^2 = 1/2*1.204*25^2 = 376.25 joules So one cubic meter of air moving at 25 meters per second has a total kinetic energy of 376.25 joules. so an air stream moving through your intake at 25m/s has a total energy of 25*376.25 joules = 9406.25 joules/second = 9406.25 watts. 9406.25 watts = 12.61 horsepower. That is the TOTAL amount of energy in the moving air. So IF: You have a 3.3 foot by 3.3 foot intake The car is moving ~55MPH You slow the exit air to ZERO velocity (not possible or you just made a vacuum behind the car) Your turbine extracts 100% of the energy from the moving air Your energy conversion system is 100% efficient THEN you theoretically can extract 12 horsepower. In reality you cannot hope to get better than 20% efficiency in the whole system ( and THAT is generous) for a whopping 2.4 hp. Now sorry but that is just plain "physics". The above assumes a stationary car in a wind tunnel for simplicity. A car moving through stationary air is even less "efficient" Care to share any of your calculations? "Mr. Engineer" |
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