L-Jet Resistor Pack repair? Options

[Rob-O]

I know the L-Jet resistor packs are NLA, and while getting my parts ready for refitting the FI on the car I noticed this. I attempted to solder the wire back on to the resistor with no luck, but I'll admit, my solder gun (and solder skills) suck.

I thought when I talked to Clay awhile back he said that tesistor packs from other cars could be used but that the plug end was singular to the 914.

So is there a pack I can get, pull the wires from the plug and put into the 914 plug? Should I attempt to find someone who can solder and have them attempt to repair? Or should I just look for a used one in the classifieds?

I would ask Clay but haven't been able to get in touch with him. I thought he was going on a 914 outing this week (Talemina?).

[Bartlett 914]

I measure 6.2 Ohm. Using 14 volts as a reference, I get 32 watts required. I would use a 50 watt chassis mount resistor. Mouser electronics has them for about 4 to 8 each.

Mouser electronics

[Mark Henry]

I measure 6.2 Ohm. Using 14 volts as a reference, I get 32 watts required. I would use a 50 watt chassis mount resistor. Mouser electronics has them for about 4 to 8 each.

Mouser electronics

6.2 ohm doesn't sound right for the injector, I'd expect closer to 3 ohms.
Or do you mean the resistor?
You don't want much more than 1 AMP going through the board.

You are using 2 resistors so 20w (each) should be OK.

I think this is the correct math, I'm I right ?
13.2v/(X+ injector ohm)=AMP

[Bartlett 914]

I measure 6.2 Ohm. Using 14 volts as a reference, I get 32 watts required. I would use a 50 watt chassis mount resistor. Mouser electronics has them for about 4 to 8 each.

Mouser electronics

6.2 ohm doesn't sound right for the injector, I'd expect closer to 3 ohms.
Or do you mean the resistor?
You don't want much more than 1 AMP going through the board.

You are using 2 resistors so 20w (each) should be OK.

I think this is the correct math, I'm I right ?
13.2v/(X+ injector ohm)=AMP

6.2 is the resistor not the injector. This is what I measured on a pack I have here. I based my calculations on an injector getting shorted to calculate the wattage.

Parallel resistors will double the wattage but half the resistance. No need to do this. The link to Mouser has reasonable prices to make a new pack and it would look neater than doubling up on components. Overall I think it will make a smaller pack.

[Mark Henry]

I measure 6.2 Ohm. Using 14 volts as a reference, I get 32 watts required. I would use a 50 watt chassis mount resistor. Mouser electronics has them for about 4 to 8 each.

Mouser electronics

6.2 ohm doesn't sound right for the injector, I'd expect closer to 3 ohms.
Or do you mean the resistor?
You don't want much more than 1 AMP going through the board.

You are using 2 resistors so 20w (each) should be OK.

I think this is the correct math, I'm I right ?
13.2v/(X+ injector ohm)=AMP

6.2 is the resistor not the injector. This is what I measured on a pack I have here. I based my calculations on an injector getting shorted to calculate the wattage.

Parallel resistors will double the wattage but half the resistance. No need to do this. The link to Mouser has reasonable prices to make a new pack and it would look neater than doubling up on components. Overall I think it will make a smaller pack.

Are you saying use one resistor?

My SDS uses a pair resistors for low impedance injectors, so does OE, I think about every pack I've seen does.
There has to be a reason for this, companies don't waste money if they don't have to.

[Dave_Darling]

Are you saying use one resistor?

IIRC, the L-jet setup uses four resistors, one for each injector power wire.

--DD

[ClayPerrine]

Are you saying use one resistor?

IIRC, the L-jet setup uses four resistors, one for each injector power wire.

--DD

You remember right.

And you can pick up the Japanese versions of the resistor packs for less than 5 bucks at a wrecking yard. And the Japanese versions don't break the wires inside the the Bosch ones.